LeetCode 3417: Zigzag Grid Traversal With Skip Solution

Master LeetCode problem 3417 (Zigzag Grid Traversal With Skip), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3417. Zigzag Grid Traversal With Skip

Easy

Array Matrix Simulation

Problem Explanation

Explanation

To solve this problem, we can simulate the zigzag traversal with skips. We will iterate through the grid following the zigzag pattern while skipping every alternate cell. We can keep track of the direction of traversal (right or left) and the row and column indices to determine the next cell to visit.

Algorithm:

Initialize variables for row and column indices, direction of traversal, and a boolean flag to determine whether to skip the next cell.
Iterate through the grid following the zigzag traversal pattern while considering the skip condition.
Add the values of the cells visited to the result array.
Return the result array.

Time Complexity

The time complexity of this algorithm is O(m * n) where m is the number of rows and n is the number of columns in the grid.

Space Complexity

The space complexity of this algorithm is O(m * n) for storing the result array.

Solution Code

class Solution {
    public int[] findDiagonalOrder(int[][] grid) {
        int m = grid.length;
        int n = grid[0].length;
        int[] result = new int[m * n];
        int row = 0, col = 0, idx = 0;
        boolean skip = false;
        int[][] directions = {{0, 1}, {1, 0}};
        
        for (int i = 0; i < m * n; i++) {
            result[idx++] = grid[row][col];
            
            if (skip) {
                skip = false;
            } else {
                row += directions[idx % 2][0];
                col += directions[idx % 2][1];
                if (row >= m) {
                    row = m - 1;
                    col += 2;
                    skip = true;
                } else if (col >= n) {
                    col = n - 1;
                    row += 2;
                    skip = true;
                } else if (row < 0) {
                    row = 0;
                    skip = true;
                } else if (col < 0) {
                    col = 0;
                    skip = true;
                }
            }
        }
        
        return result;
    }
}

Try It Yourself

Loading code editor...

Frequently Asked Questions

How to solve LeetCode 3417 (Zigzag Grid Traversal With Skip)?

This page provides optimized solutions for LeetCode problem 3417 (Zigzag Grid Traversal With Skip) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test your code.

What is the time complexity of LeetCode 3417 (Zigzag Grid Traversal With Skip)?

The time complexity for LeetCode 3417 (Zigzag Grid Traversal With Skip) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

Can I run code for LeetCode 3417 on DevExCode?

Yes, DevExCode provides an interactive code editor where you can write, test, and run your code for LeetCode 3417 in Java, C++, or Python.

Back to LeetCode Solutions