LeetCode 3424: Minimum Cost to Make Arrays Identical Solution

Master LeetCode problem 3424 (Minimum Cost to Make Arrays Identical), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3424. Minimum Cost to Make Arrays Identical

Medium

Array Greedy Sorting

Problem Explanation

Explanation

To solve this problem, we can iterate through the arrays arr and brr simultaneously and for each element in arr, we calculate the absolute difference between the corresponding elements in arr and brr. We then add this difference to a priority queue and remove the largest k elements from the priority queue, as we only need to minimize the total cost.

The priority queue helps us keep track of the largest differences, and by removing the largest k elements, we ensure that we minimize the total cost. Finally, we return the sum of the remaining elements in the priority queue as the minimum total cost.

Time Complexity: O(n log n) where n is the length of the arrays arr and brr. Space Complexity: O(n) where n is the length of the arrays arr and brr.

Solution Code

import java.util.PriorityQueue;

class Solution {
    public int minCost(int[] arr, int[] brr, int k) {
        int n = arr.length;
        PriorityQueue<Integer> pq = new PriorityQueue<>((a, b) -> b - a);

        for (int i = 0; i < n; i++) {
            pq.offer(Math.abs(arr[i] - brr[i]));
        }

        while (k > 0) {
            pq.poll();
            k--;
        }

        int totalCost = 0;
        while (!pq.isEmpty()) {
            totalCost += pq.poll();
        }

        return totalCost;
    }
}

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