LeetCode 3434: Maximum Frequency After Subarray Operation Solution

Master LeetCode problem 3434 (Maximum Frequency After Subarray Operation), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3434. Maximum Frequency After Subarray Operation

Medium

Array Hash Table Dynamic Programming Greedy Enumeration Prefix Sum

Problem Explanation

Explanation

To solve this problem, we can iterate through all possible subarrays and perform the given operation on each subarray. For each subarray, we calculate the frequency of the target value k after the operation. We keep track of the maximum frequency found among all subarrays and return it as the result.

Start by initializing a variable maxFreq to store the maximum frequency of k.
Iterate through all subarrays using two nested loops:
- Within the inner loop, perform the operation by adding a value x to all elements in the current subarray.
- Calculate the frequency of k after the operation and update maxFreq if the frequency is greater.
Return the maxFreq as the final result.

Solution Code

class Solution {
    public int maxFrequency(int[] nums, int k) {
        int n = nums.length;
        int maxFreq = 0;
        
        for (int i = 0; i < n; i++) {
            for (int j = i; j < n; j++) {
                int sum = 0;
                for (int l = i; l <= j; l++) {
                    sum += nums[l];
                }
                int freq = (sum + k) / (j - i + 1);
                if (freq == k) {
                    maxFreq = Math.max(maxFreq, j - i + 1);
                }
            }
        }
        
        return maxFreq;
    }
}

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