LeetCode 3438: Find Valid Pair of Adjacent Digits in String Solution
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3438. Find Valid Pair of Adjacent Digits in String
Problem Explanation
Explanation:
To solve this problem, we will iterate over the string s from left to right, keeping track of the frequency of each digit. We will check adjacent pairs of digits to see if they form a valid pair according to the given conditions. If we find a valid pair, we return it; otherwise, we continue iterating until the end of the string.
Algorithm:
- Initialize a frequency map to keep track of the count of each digit in the string.
- Iterate over the string from left to right.
- For each pair of adjacent digits, check if they form a valid pair.
- If a valid pair is found, return the pair.
- If no valid pair is found after iterating through the entire string, return an empty string.
Time Complexity: O(n), where n is the length of the input string s.
Space Complexity: O(1) - Although we use a map to store the frequency of digits, the space used is constant since there are only 9 possible digits.
:
Solution Code
class Solution {
public String findValidPair(String s) {
Map<Character, Integer> freq = new HashMap<>();
for (int i = 0; i < s.length() - 1; i++) {
char curr = s.charAt(i);
char next = s.charAt(i + 1);
freq.put(curr, freq.getOrDefault(curr, 0) + 1);
freq.put(next, freq.getOrDefault(next, 0) + 1);
if (curr != next && freq.get(curr) == (curr - '0') && freq.get(next) == (next - '0')) {
return "" + curr + next;
}
}
return "";
}
}Try It Yourself
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