LeetCode 3442: Maximum Difference Between Even and Odd Frequency I Solution

Master LeetCode problem 3442 (Maximum Difference Between Even and Odd Frequency I), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3442. Maximum Difference Between Even and Odd Frequency I

Easy

Hash Table String Counting

Problem Explanation

Explanation

To solve this problem, we need to find the frequencies of all characters in the given string s. Then, we iterate through the frequencies to find the maximum difference between the frequency of a character with even frequency and a character with odd frequency.

Create a hashmap to store the frequencies of each character in the string.
Iterate through the string s and update the frequencies in the hashmap.
Iterate through the hashmap and find the maximum difference between the frequency of a character with even frequency and a character with odd frequency.

Time Complexity: O(n)
Space Complexity: O(n)

Solution Code

import java.util.HashMap;
import java.util.Map;

class Solution {
    public int maxDifference(String s) {
        Map<Character, Integer> freqMap = new HashMap<>();
        for (char c : s.toCharArray()) {
            freqMap.put(c, freqMap.getOrDefault(c, 0) + 1);
        }
        
        int maxEven = 0, maxOdd = 0;
        for (int freq : freqMap.values()) {
            if (freq % 2 == 0) {
                maxEven = Math.max(maxEven, freq);
            } else {
                maxOdd = Math.max(maxOdd, freq);
            }
        }
        
        return maxOdd - maxEven;
    }
}

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