LeetCode 3443: Maximum Manhattan Distance After K Changes Solution

Master LeetCode problem 3443 (Maximum Manhattan Distance After K Changes), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3443. Maximum Manhattan Distance After K Changes

Medium

Hash Table Math String Counting

Problem Explanation

Explanation:

To solve this problem, we can iterate through the string s and calculate the Manhattan distance after each change. We can try changing each character to all four directions and calculate the Manhattan distance for each change. We should keep track of the maximum Manhattan distance achievable.

Algorithm:

Initialize variables maxDistance to 0 and currentDistance to 0.
Iterate through the string s:
- For each character in s, calculate the Manhattan distance by updating the currentDistance.
- For each change, try changing the character to all four directions and calculate the Manhattan distance.
- Update the maxDistance with the maximum achievable Manhattan distance.
Return the maxDistance.

Time Complexity:

The time complexity of this solution is O(n^2), where n is the length of the input string s.

Space Complexity:

The space complexity of this solution is O(1) as we are using only a constant amount of extra space.

Solution Code

class Solution {
    public int maxDistance(String s, int k) {
        int maxDistance = 0;
        for (int i = 0; i < s.length(); i++) {
            int currentDistance = 0;
            for (char c = 'N'; c <= 'W'; c++) {
                int changes = 0;
                for (int j = i; j < s.length(); j++) {
                    if (s.charAt(j) != c) {
                        changes++;
                    }
                    if (changes <= k) {
                        currentDistance = Math.max(currentDistance, Math.abs(j - i) + Math.abs(changes - k));
                    }
                }
            }
            maxDistance = Math.max(maxDistance, currentDistance);
        }
        return maxDistance;
    }
}

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