LeetCode 3458: Select K Disjoint Special Substrings Solution
Master LeetCode problem 3458 (Select K Disjoint Special Substrings), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3458. Select K Disjoint Special Substrings
Problem Explanation
Explanation:
To solve this problem, we can use a greedy approach. We iterate over the string s character by character. For each character, we keep track of the special substrings we have found and the characters that have been used in those substrings. If we encounter a character that is not used in any special substring, we can create a new special substring with that character. If we encounter a character that is used in a special substring, we move on to the next character. We continue this process until we have found k disjoint special substrings or until we reach the end of the string.
Time Complexity:
The time complexity of this approach is O(n), where n is the length of the input string s.
Space Complexity:
The space complexity of this approach is O(1) since we are using a constant amount of extra space to store the characters used in the special substrings.
Solution Code
public boolean canChoose(String s, int k) {
boolean[] used = new boolean[26];
int count = 0;
for (char c : s.toCharArray()) {
if (!used[c - 'a']) {
used[c - 'a'] = true;
count++;
if (count == k) {
return true;
}
}
}
return false;
}Try It Yourself
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