LeetCode 3467: Transform Array by Parity Solution

Master LeetCode problem 3467 (Transform Array by Parity), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3467. Transform Array by Parity

Easy

Array Sorting Counting

Problem Explanation

Explanation

To solve this problem, we can follow these steps:

Iterate through the array and replace even numbers with 0 and odd numbers with 1.
Sort the modified array in non-decreasing order.

Time complexity: O(n log n) where n is the number of elements in the array. Space complexity: O(1) since we are modifying the input array in place.

Solution Code

class Solution {
    public int[] transformArray(int[] nums) {
        for (int i = 0; i < nums.length; i++) {
            if (nums[i] % 2 == 0) {
                nums[i] = 0;
            } else {
                nums[i] = 1;
            }
        }
        Arrays.sort(nums);
        return nums;
    }
}

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