LeetCode 3471: Find the Largest Almost Missing Integer Solution

Master LeetCode problem 3471 (Find the Largest Almost Missing Integer), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3471. Find the Largest Almost Missing Integer

Problem Explanation

Explanation:

To solve this problem, we can iterate through all possible subarrays of size k within the given array nums. For each subarray, we count the frequency of each element. If an element appears only once in any subarray, we update the largest almost missing integer seen so far.

Algorithm:

  1. Initialize a HashMap to store the frequency of elements in each subarray.
  2. Iterate through all subarrays of size k within nums.
  3. For each subarray, update the frequency count of each element in the HashMap.
  4. Check if any element appears only once in the subarray. If yes, update the largest almost missing integer.
  5. Return the largest almost missing integer found.

Time Complexity:

The time complexity of this approach is O(n * k) where n is the length of the input array nums and k is the given size of the subarray.

Space Complexity:

The space complexity is O(n) for storing the frequencies of elements in each subarray.

:

Solution Code

class Solution {
    public int largestAlmostMissingInteger(int[] nums, int k) {
        HashMap<Integer, Integer> freq = new HashMap<>();
        int maxAlmostMissing = -1;

        for (int i = 0; i <= nums.length - k; i++) {
            freq.clear();
            for (int j = i; j < i + k; j++) {
                freq.put(nums[j], freq.getOrDefault(nums[j], 0) + 1);
            }

            for (int num : freq.keySet()) {
                if (freq.get(num) == 1) {
                    maxAlmostMissing = Math.max(maxAlmostMissing, num);
                }
            }
        }

        return maxAlmostMissing;
    }
}

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