LeetCode 3489: Zero Array Transformation IV Solution

Master LeetCode problem 3489 (Zero Array Transformation IV), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3489. Zero Array Transformation IV

Medium

Array Dynamic Programming

Problem Explanation

Explanation:

To solve this problem, we need to iterate over the queries and simulate the decrements on the nums array. We keep track of the count of queries processed and check if the array becomes a Zero Array after processing each query. If it becomes a Zero Array, we return the count of queries processed.

Algorithmic Idea:

Initialize a counter k to 0.
Iterate over each query and decrement the values in the nums array accordingly.
After each query, check if the array becomes a Zero Array. If it does, return the current count k.
If no Zero Array is obtained after processing all queries, return -1.

Time Complexity:

The time complexity of this solution is O(n + q), where n is the length of the nums array and q is the number of queries.

Space Complexity:

The space complexity is O(1) as we are not using any extra data structures.

Solution Code

class Solution {
    public int minNonZero(int[] nums, int[][] queries) {
        int k = 0;
        for (int[] query : queries) {
            int l = query[0];
            int r = query[1];
            int val = query[2];
            
            for (int i = l; i <= r; i++) {
                nums[i] -= val;
            }
            
            k++;
            
            if (isZeroArray(nums)) {
                return k;
            }
        }
        
        return -1;
    }
    
    private boolean isZeroArray(int[] nums) {
        for (int num : nums) {
            if (num != 0) {
                return false;
            }
        }
        return true;
    }
}

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