LeetCode 349: Intersection of Two Arrays Solution

Master LeetCode problem 349 (Intersection of Two Arrays), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

349. Intersection of Two Arrays

Problem Explanation

Explanation

To find the intersection of two arrays, we can use a set to store unique elements of one array and then iterate through the other array to check for common elements. We can use a set to ensure uniqueness of elements in the result.

  1. Create a set set1 to store unique elements of nums1.
  2. Iterate through nums2 and check if the element exists in set1. If it does, add it to the result set.
  3. Convert the result set to an array and return it.

Time complexity: O(n + m) where n and m are the lengths of the two input arrays.

Space complexity: O(min(n, m)) where n and m are the lengths of the two input arrays.

Solution Code

import java.util.HashSet;
import java.util.Set;
import java.util.Arrays;

class Solution {
    public int[] intersection(int[] nums1, int[] nums2) {
        Set<Integer> set1 = new HashSet<>();
        for (int num : nums1) {
            set1.add(num);
        }
        
        Set<Integer> resultSet = new HashSet<>();
        for (int num : nums2) {
            if (set1.contains(num)) {
                resultSet.add(num);
            }
        }
        
        int[] result = new int[resultSet.size()];
        int index = 0;
        for (int num : resultSet) {
            result[index++] = num;
        }
        
        return result;
    }
}

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