LeetCode 3498: Reverse Degree of a String Solution
Master LeetCode problem 3498 (Reverse Degree of a String), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3498. Reverse Degree of a String
Problem Explanation
Explanation
To solve this problem, we need to calculate the reverse degree of a given string s based on the rules provided. For each character in the string, we calculate the product of its position in the reversed alphabet and its position in the string, then sum up these products to get the reverse degree.
- Iterate through each character in the string.
- Calculate the position of the character in the reversed alphabet.
- Multiply this position with the 1-based index of the character in the string.
- Sum up these products for all characters to get the reverse degree.
Time Complexity: O(n) where n is the length of the input string s.
Space Complexity: O(1)
Solution Code
class Solution {
public int reverseDegree(String s) {
int reverseDegree = 0;
for (int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
int positionInReverseAlphabet = 26 - (c - 'a');
reverseDegree += positionInReverseAlphabet * (i + 1);
}
return reverseDegree;
}
}Try It Yourself
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