LeetCode 3510: Minimum Pair Removal to Sort Array II Solution

Master LeetCode problem 3510 (Minimum Pair Removal to Sort Array II), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3510. Minimum Pair Removal to Sort Array II

Hard

Array Hash Table Linked List Heap (Priority Queue)Simulation Doubly-Linked List Ordered Set

Problem Explanation

Explanation

To solve this problem, we can iterate through the array and check each adjacent pair of elements. If the current pair is not in non-decreasing order, we can merge them into a single element by taking their sum. We repeat this process until the entire array becomes non-decreasing. The key observation is that choosing the leftmost smallest pair ensures the minimum number of operations needed.

Time Complexity: O(n) Space Complexity: O(1)

Solution Code

class Solution {
    public int minPairRemovals(int[] nums) {
        int count = 0;
        for (int i = 1; i < nums.length; i++) {
            if (nums[i] < nums[i - 1]) {
                count += Math.abs(nums[i] - nums[i - 1]);
                nums[i] = nums[i - 1];
            }
        }
        return count;
    }
}

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