LeetCode 3513: Number of Unique XOR Triplets I Solution

Master LeetCode problem 3513 (Number of Unique XOR Triplets I), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3513. Number of Unique XOR Triplets I

Medium

Array Math Bit Manipulation

Problem Explanation

Explanation

To solve this problem, we can iterate through all possible triplets (i, j, k) and calculate the XOR value for each triplet. We will then store the unique XOR values in a set to avoid duplicates. Finally, we return the size of the set which represents the number of unique XOR triplet values.

Initialize a set to store unique XOR values.
Iterate through all possible triplets (i, j, k) where i <= j <= k.
Calculate the XOR value for the triplet (nums[i] XOR nums[j] XOR nums[k]).
Add the XOR value to the set.
Return the size of the set as the result.

Time Complexity: O(n^3) where n is the length of the input array. Space Complexity: O(n^3) to store the unique XOR values.

Solution Code

class Solution {
    public int countTriplets(int[] nums) {
        Set<Integer> xorSet = new HashSet<>();
        int n = nums.length;
        
        for (int i = 0; i < n; i++) {
            for (int j = i; j < n; j++) {
                for (int k = j; k < n; k++) {
                    xorSet.add(nums[i] ^ nums[j] ^ nums[k]);
                }
            }
        }
        
        return xorSet.size();
    }
}

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