LeetCode 3514: Number of Unique XOR Triplets II Solution

Master LeetCode problem 3514 (Number of Unique XOR Triplets II), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3514. Number of Unique XOR Triplets II

Medium

Array Math Bit Manipulation Enumeration

Problem Explanation

Explanation

To solve this problem, we can iterate over all possible triplets of elements in the array and calculate their XOR value. We can store these unique XOR values in a HashSet to avoid duplicates. Finally, we return the size of the HashSet which represents the number of unique XOR values.

Algorithm:

Initialize a HashSet to store unique XOR values.
Iterate over all possible triplets (i, j, k) in the array.
Calculate the XOR value of the triplet (nums[i] ^ nums[j] ^ nums[k]).
Add the XOR value to the HashSet.
Return the size of the HashSet.

Time Complexity: O(n^3) where n is the number of elements in the array. Space Complexity: O(n^3) to store all unique XOR values.

Solution Code

class Solution {
    public int countTriplets(int[] nums) {
        Set<Integer> xorValues = new HashSet<>();
        int n = nums.length;
        
        for (int i = 0; i < n; i++) {
            for (int j = i; j < n; j++) {
                for (int k = j; k < n; k++) {
                    xorValues.add(nums[i] ^ nums[j] ^ nums[k]);
                }
            }
        }
        
        return xorValues.size();
    }
}

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