LeetCode 3516: Find Closest Person Solution

Problem Explanation

Explanation

To solve this problem, we need to calculate the number of steps it takes for each Person 1 and Person 2 to reach Person 3. We can find this by calculating the absolute difference between the positions of Person 1 and Person 3, and Person 2 and Person 3, and then dividing by 2 (since both Person 1 and Person 2 move towards Person 3 at the same speed).

After calculating the steps for both Person 1 and Person 2, we can compare the results to determine which person arrives first or if they arrive at the same time.

Time complexity: O(1) as the algorithm is constant time.
Space complexity: O(1) as we are using only a constant amount of extra space.

Solution Code

class Solution {
    public int findClosestPerson(int x, int y, int z) {
        int stepsX = Math.abs(x - z) / 2;
        int stepsY = Math.abs(y - z) / 2;
        
        if (stepsX < stepsY) {
            return 1;
        } else if (stepsX > stepsY) {
            return 2;
        } else {
            return 0;
        }
    }
}

Frequently Asked Questions

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What is the time complexity of LeetCode 3516 (Find Closest Person)?

The time complexity for LeetCode 3516 (Find Closest Person) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

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3516. Find Closest Person