LeetCode 361: Bomb Enemy Solution
Master LeetCode problem 361 (Bomb Enemy), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
361. Bomb Enemy
Problem Explanation
Explanation:
To solve this problem, we can iterate over each cell of the grid and calculate the maximum number of enemies that can be killed by placing a bomb at that cell. For each cell, we can calculate the number of enemies that can be killed by the bomb placed in that cell by counting the number of enemies in the same row and column. We can then update the maximum number of enemies killed for that cell. :
Solution Code
class Solution {
public int maxKilledEnemies(char[][] grid) {
if (grid == null || grid.length == 0 || grid[0].length == 0) {
return 0;
}
int m = grid.length;
int n = grid[0].length;
int result = 0;
int rowCount = 0;
int[] colCount = new int[n];
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
if (j == 0 || grid[i][j - 1] == 'W') {
rowCount = 0;
for (int k = j; k < n && grid[i][k] != 'W'; k++) {
rowCount += grid[i][k] == 'E' ? 1 : 0;
}
}
if (i == 0 || grid[i - 1][j] == 'W') {
colCount[j] = 0;
for (int k = i; k < m && grid[k][j] != 'W'; k++) {
colCount[j] += grid[k][j] == 'E' ? 1 : 0;
}
}
if (grid[i][j] == '0') {
result = Math.max(result, rowCount + colCount[j]);
}
}
}
return result;
}
}Try It Yourself
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