LeetCode 412: Fizz Buzz Solution

Master LeetCode problem 412 (Fizz Buzz), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

412. Fizz Buzz

Easy

Math String Simulation

Problem Explanation

Explanation

We iterate from 1 to n and for each number, we check if it is divisible by 3, 5, or both.
If it is divisible by both 3 and 5, we add "FizzBuzz" to the answer array.
If it is divisible by 3 only, we add "Fizz" to the answer array.
If it is divisible by 5 only, we add "Buzz" to the answer array.
If none of the above conditions are met, we add the number itself as a string to the answer array.

Time Complexity: O(n) where n is the input integer.

Space Complexity: O(1) excluding the space required for the output array.

Solution Code

class Solution {
    public List<String> fizzBuzz(int n) {
        List<String> answer = new ArrayList<>();
        
        for (int i = 1; i <= n; i++) {
            if (i % 3 == 0 && i % 5 == 0) {
                answer.add("FizzBuzz");
            } else if (i % 3 == 0) {
                answer.add("Fizz");
            } else if (i % 5 == 0) {
                answer.add("Buzz");
            } else {
                answer.add(String.valueOf(i));
            }
        }
        
        return answer;
    }
}

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