LeetCode 413: Arithmetic Slices Solution
Master LeetCode problem 413 (Arithmetic Slices), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
413. Arithmetic Slices
Problem Explanation
Explanation
To solve this problem, we can iterate through the array and check if the current element, along with its previous elements, form an arithmetic sequence. We can keep track of the count of valid arithmetic subarrays. If an arithmetic sequence is extended by adding the current element, we increment the count by 1. We maintain a variable count to track the number of valid arithmetic subarrays.
Time complexity: O(n) where n is the number of elements in the array
Space complexity: O(1)
Solution Code
class Solution {
public int numberOfArithmeticSlices(int[] nums) {
if (nums == null || nums.length < 3) {
return 0;
}
int count = 0;
int result = 0;
for (int i = 2; i < nums.length; i++) {
if (nums[i] - nums[i-1] == nums[i-1] - nums[i-2]) {
count++;
result += count;
} else {
count = 0;
}
}
return result;
}
}Try It Yourself
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