LeetCode 462: Minimum Moves to Equal Array Elements II Solution
Master LeetCode problem 462 (Minimum Moves to Equal Array Elements II), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation
To find the minimum number of moves required to make all array elements equal, we can follow the following approach:
- Sort the input array.
- Calculate the median of the sorted array.
- Iterate through the array and calculate the sum of absolute differences between each element and the median.
This approach works because the median is the optimal solution that minimizes the sum of absolute differences.
Time Complexity: O(n*log(n)) due to sorting the array.
Space Complexity: O(1) as we are not using any extra space other than a few variables.
Solution Code
import java.util.Arrays;
class Solution {
public int minMoves2(int[] nums) {
Arrays.sort(nums);
int median = nums[nums.length / 2];
int moves = 0;
for (int num : nums) {
moves += Math.abs(num - median);
}
return moves;
}
}Try It Yourself
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