LeetCode 464: Can I Win Solution
Master LeetCode problem 464 (Can I Win), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
464. Can I Win
Problem Explanation
Explanation
To solve this problem, we can use a recursive approach with memoization to keep track of the states and avoid recomputation. We can simulate the game by trying all possible moves at each step and check if any move leads to a win. We need to consider the current total, the remaining numbers available, and the player taking the turn.
- Create a hashmap to store the state as the key and the result (win or lose) as the value.
- Define a recursive function
canWinthat takes the current total and the set of remaining numbers. - Check if the current state is already computed in the hashmap, return the result if it exists.
- Iterate through all available numbers.
- For each number, if it is not used yet, check if the opponent loses by choosing that number.
- If the opponent loses, mark the current player as a winner and return true.
- If no winning move is found, mark the current player as a loser and return false.
- Update the hashmap with the current state and the result.
- Call the
canWinfunction with the initial total and the set of all numbers. - Return the result of the function.
Solution Code
class Solution {
public boolean canIWin(int maxChoosableInteger, int desiredTotal) {
if (maxChoosableInteger * (maxChoosableInteger + 1) / 2 < desiredTotal) return false;
return canWin(desiredTotal, (1 << maxChoosableInteger) - 1, new HashMap<>());
}
private boolean canWin(int total, int state, Map<Integer, Boolean> memo) {
if (total <= 0) return false;
if (memo.containsKey(state)) return memo.get(state);
for (int i = 0; i < 20; i++) {
if ((state & (1 << i)) > 0) {
if (!canWin(total - i - 1, state & ~(1 << i), memo)) {
memo.put(state, true);
return true;
}
}
}
memo.put(state, false);
return false;
}
}Try It Yourself
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