LeetCode 467: Unique Substrings in Wraparound String Solution

Master LeetCode problem 467 (Unique Substrings in Wraparound String), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

467. Unique Substrings in Wraparound String

Medium

String Dynamic Programming

Problem Explanation

Explanation:

To solve this problem, we can iterate through the input string s and keep track of the longest contiguous substring ending at each character. We can use an array count to store the maximum length of substring ending at each character. Then, we can calculate the total number of unique substrings by summing up the values in the count array.

Algorithmic Idea:

Initialize an array count of size 26 to store the maximum length of substring ending at each character.
Iterate through the input string s.
For each character in s, update the maximum length of substring ending at that character.
Calculate the total number of unique substrings by summing up the values in the count array.

Time Complexity:

The time complexity of this algorithm is O(n), where n is the length of the input string s.

Space Complexity:

The space complexity of this algorithm is O(1) since we are using a constant amount of extra space.

Solution Code

class Solution {
    public int findSubstringInWraproundString(String s) {
        if (s == null || s.length() == 0) {
            return 0;
        }
        
        int[] count = new int[26];
        int maxLength = 0;
        
        for (int i = 0; i < s.length(); i++) {
            if (i > 0 && (s.charAt(i) == s.charAt(i - 1) + 1 || s.charAt(i) == s.charAt(i - 1) - 25)) {
                maxLength++;
            } else {
                maxLength = 1;
            }
            
            int index = s.charAt(i) - 'a';
            count[index] = Math.max(count[index], maxLength);
        }
        
        return Arrays.stream(count).sum();
    }
}

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