LeetCode 477: Total Hamming Distance Solution
Master LeetCode problem 477 (Total Hamming Distance), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
477. Total Hamming Distance
Problem Explanation
Explanation
To solve this problem efficiently, we can observe that the Hamming distance between two numbers can be calculated by counting the number of set bits (bits with value 1) in their XOR result. We can iterate through each bit position (from 0 to 31 for integers) and count the number of elements that have that bit set and the number of elements that have that bit unset. The total Hamming distance is then the product of these two counts for each bit position summed up.
Solution Code
class Solution {
public int totalHammingDistance(int[] nums) {
int totalDistance = 0;
for (int i = 0; i < 32; i++) {
int setBits = 0;
for (int num : nums) {
if ((num & (1 << i)) != 0) {
setBits++;
}
}
totalDistance += setBits * (nums.length - setBits);
}
return totalDistance;
}
}Try It Yourself
Loading code editor...
Related LeetCode Problems
Frequently Asked Questions
How to solve LeetCode 477 (Total Hamming Distance)?
This page provides optimized solutions for LeetCode problem 477 (Total Hamming Distance) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test your code.
What is the time complexity of LeetCode 477 (Total Hamming Distance)?
The time complexity for LeetCode 477 (Total Hamming Distance) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.
Can I run code for LeetCode 477 on DevExCode?
Yes, DevExCode provides an interactive code editor where you can write, test, and run your code for LeetCode 477 in Java, C++, or Python.