LeetCode 500: Keyboard Row Solution
Master LeetCode problem 500 (Keyboard Row), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
500. Keyboard Row
Problem Explanation
Explanation:
- Create a set for each row of the keyboard with the characters in that row.
- Iterate over each word in the input array and check if all characters in the word belong to the same row of the keyboard.
- If a word meets the criteria, add it to the result list.
Time Complexity: O(n * m) where n is the number of words and m is the average length of a word. Space Complexity: O(1) since the size of the keyboard rows is fixed.
:
Solution Code
class Solution {
public String[] findWords(String[] words) {
String[] rows = new String[]{"qwertyuiop", "asdfghjkl", "zxcvbnm"};
List<String> result = new ArrayList<>();
for (String word : words) {
if (checkWordInRow(word.toLowerCase(), rows)) {
result.add(word);
}
}
return result.toArray(new String[result.size()]);
}
private boolean checkWordInRow(String word, String[] rows) {
for (String row : rows) {
boolean inSameRow = true;
for (char c : word.toCharArray()) {
if (row.indexOf(c) == -1) {
inSameRow = false;
break;
}
}
if (inSameRow) {
return true;
}
}
return false;
}
}Try It Yourself
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