LeetCode 605: Can Place Flowers Solution

Problem Explanation

Explanation

To solve this problem, we can iterate through the flowerbed array and check if we can plant a flower at a particular position by considering the current position, the previous position, and the next position. If all these positions are empty (0), we can plant a flower at the current position. We update the count of planted flowers and continue checking for the next positions until we reach the end of the flowerbed or we have planted enough flowers. Finally, we compare the count of planted flowers with the required number of flowers to be planted and return true if the count is greater than or equal to n.

Time complexity: O(n), where n is the length of the flowerbed array.
Space complexity: O(1) as we are using constant extra space.

Solution Code

class Solution {
    public boolean canPlaceFlowers(int[] flowerbed, int n) {
        int count = 0;
        int i = 0;
        while (i < flowerbed.length) {
            if (flowerbed[i] == 0 && (i == 0 || flowerbed[i - 1] == 0) && (i == flowerbed.length - 1 || flowerbed[i + 1] == 0)) {
                flowerbed[i] = 1;
                count++;
            }
            i++;
        }
        return count >= n;
    }
}

Frequently Asked Questions

How to solve LeetCode 605 (Can Place Flowers)?

This page provides optimized solutions for LeetCode problem 605 (Can Place Flowers) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test your code.

What is the time complexity of LeetCode 605 (Can Place Flowers)?

The time complexity for LeetCode 605 (Can Place Flowers) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

Can I run code for LeetCode 605 on DevExCode?

Yes, DevExCode provides an interactive code editor where you can write, test, and run your code for LeetCode 605 in Java, C++, or Python.