LeetCode 628: Maximum Product of Three Numbers Solution

Master LeetCode problem 628 (Maximum Product of Three Numbers), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

628. Maximum Product of Three Numbers

Easy

Array Math Sorting

Problem Explanation

Explanation

To find the maximum product of three numbers in the given array, we can sort the array and consider two cases:

The product of the three largest numbers (if there are positive numbers in the array).
The product of the two smallest numbers (which will be negative) and the largest number (to account for negative numbers in the array).

By comparing these two cases, we can determine the maximum product of three numbers.

Sort the input array.
Calculate the products of the two smallest numbers and the largest number, and the product of the three largest numbers.
Return the maximum of these two products.

Time complexity: O(nlogn) due to sorting the input array. Space complexity: O(1)

Solution Code

class Solution {
    public int maximumProduct(int[] nums) {
        Arrays.sort(nums);
        int n = nums.length;
        int option1 = nums[n-1] * nums[n-2] * nums[n-3];
        int option2 = nums[0] * nums[1] * nums[n-1];
        return Math.max(option1, option2);
    }
}

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