636. Exclusive Time of Functions

Explanation

To solve this problem, we can simulate the execution of functions using a stack to keep track of the start and end times of each function. We iterate through the logs and update the exclusive time for each function accordingly.

Here's the algorithm:

Initialize an array exclusiveTime of size n to store the exclusive time for each function.
Initialize a stack stack to keep track of functions.
Iterate through each log:
- Split the log into function ID, event (start/end), and timestamp.
- If the event is a start event:
  - If the stack is not empty, update the exclusive time of the function at the top of the stack.
  - Push the function ID and timestamp onto the stack.
- If the event is an end event:
  - Update the exclusive time of the function at the top of the stack.
  - Pop the function ID and timestamp from the stack.
Return the exclusiveTime array.

Time complexity: O(logs.length) Space complexity: O(n)

View Leetcode Problem

class Solution {
    public int[] exclusiveTime(int n, List<String> logs) {
        int[] exclusiveTime = new int[n];
        Stack<int[]> stack = new Stack<>();

        for (String log : logs) {
            String[] parts = log.split(":");
            int functionId = Integer.parseInt(parts[0]);
            String event = parts[1];
            int timestamp = Integer.parseInt(parts[2]);

            if (event.equals("start")) {
                if (!stack.isEmpty()) {
                    int[] prev = stack.peek();
                    exclusiveTime[prev[0]] += timestamp - prev[1];
                }
                stack.push(new int[]{functionId, timestamp});
            } else {
                int[] current = stack.pop();
                exclusiveTime[functionId] += timestamp - current[1] + 1;

                if (!stack.isEmpty()) {
                    stack.peek()[1] = timestamp + 1;
                }
            }
        }

        return exclusiveTime;
    }
}

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Explanation

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