LeetCode 66: Plus One Solution
Master LeetCode problem 66 (Plus One), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation
To increment a large integer represented as an array of digits by one, we start from the least significant digit and move towards the most significant digit. We add 1 to the current digit and check if there is any carry. If there is a carry, we continue the process with the next digit. If there is no carry after incrementing the last digit, we stop and return the updated array of digits.
- Time complexity: O(n) where n is the number of digits.
- Space complexity: O(1)
Solution Code
class Solution {
public int[] plusOne(int[] digits) {
int n = digits.length;
for (int i = n - 1; i >= 0; i--) {
if (digits[i] < 9) {
digits[i]++;
return digits;
}
digits[i] = 0;
}
int[] result = new int[n + 1];
result[0] = 1;
return result;
}
}Try It Yourself
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What is the time complexity of LeetCode 66 (Plus One)?
The time complexity for LeetCode 66 (Plus One) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.
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