LeetCode 68: Text Justification Solution
Master LeetCode problem 68 (Text Justification), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
68. Text Justification
Problem Explanation
Explanation:
To solve this problem, we can follow these steps:
- Iterate over the words list and greedily form lines by adding words until the line length exceeds the
maxWidth. - Calculate the total number of spaces required to evenly distribute among words in each line.
- Handle the special case when there is only one word in a line or it is the last line.
- Construct the final result by formatting the lines with appropriate spaces.
Time Complexity: O(N), where N is the total number of characters in all words.
Space Complexity: O(N), where N is the total number of characters in all words.
:
Solution Code
class Solution {
public List<String> fullJustify(String[] words, int maxWidth) {
List<String> result = new ArrayList<>();
int start = 0;
while (start < words.length) {
int end = start + 1;
int lineLength = words[start].length();
while (end < words.length && lineLength + words[end].length() + (end - start) <= maxWidth) {
lineLength += words[end].length();
end++;
}
int spaces = maxWidth - lineLength;
int gaps = end - start - 1;
StringBuilder sb = new StringBuilder();
sb.append(words[start]);
if (gaps == 0 || end == words.length) {
for (int i = start + 1; i < end; i++) {
sb.append(" ").append(words[i]);
}
for (int i = sb.length(); i < maxWidth; i++) {
sb.append(" ");
}
} else {
int spacesPerGap = spaces / gaps;
int extraSpaces = spaces % gaps;
for (int i = start + 1; i < end; i++) {
for (int j = 0; j < spacesPerGap; j++) {
sb.append(" ");
}
if (extraSpaces > 0) {
sb.append(" ");
extraSpaces--;
}
sb.append(words[i]);
}
}
result.add(sb.toString());
start = end;
}
return result;
}
}Try It Yourself
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