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LeetCode 683: K Empty Slots Solution

Master LeetCode problem 683 (K Empty Slots), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

Problem Explanation

Explanation:

This problem asks us to find the day when there are exactly k flowers between two flowers blooming. We can solve this problem by using a sliding window approach where we keep track of the window of size k + 2 and check if there are k empty slots between the flowers in the window.

Here's the step-by-step algorithm:

  1. Initialize an array days where days[i] stores the day when the flower at position i will bloom.
  2. Initialize two pointers left and right to keep track of the window boundaries.
  3. Loop through the days array:
    • Update left and right pointers to form a window of size k + 2.
    • Check if there are k empty slots between the flowers in the window.
    • If yes, return the day number.
  4. If no valid position is found, return -1.

Time Complexity: O(n) Space Complexity: O(n)

: :

Solution Code

class Solution {
    public int kEmptySlots(int[] flowers, int k) {
        int n = flowers.length;
        int[] days = new int[n];
        for (int i = 0; i < n; i++) {
            days[flowers[i] - 1] = i + 1;
        }
        
        int left = 0, right = k + 1;
        int res = Integer.MAX_VALUE;
        
        for (int i = 1; right < n; i++) {
            if (days[i] < days[left] || days[i] <= days[right]) {
                if (i == right) {
                    res = Math.min(res, Math.max(days[left], days[right]));
                }
                left = i;
                right = i + k + 1;
            }
        }
        
        return res == Integer.MAX_VALUE ? -1 : res;
    }
}

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