LeetCode 717: 1-bit and 2-bit Characters Solution

Problem Explanation

Explanation

We iterate through the bits array and check if the current bit is 0 or 1.
If the current bit is 0, we increment the index by 1 (indicating a one-bit character).
If the current bit is 1, we increment the index by 2 (indicating a two-bit character).
Finally, we check if the index reached the last index of the array. If it did, then the last character must be a one-bit character.

Time Complexity: O(n)
Space Complexity: O(1)

Solution Code

class Solution {
    public boolean isOneBitCharacter(int[] bits) {
        int i = 0;
        while (i < bits.length - 1) {
            if (bits[i] == 0) {
                i++;
            } else {
                i += 2;
            }
        }
        return i == bits.length - 1;
    }
}

Frequently Asked Questions

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717. 1-bit and 2-bit Characters