LeetCode 718: Maximum Length of Repeated Subarray Solution

Master LeetCode problem 718 (Maximum Length of Repeated Subarray), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

718. Maximum Length of Repeated Subarray

Medium

Array Binary Search Dynamic Programming Sliding Window Rolling Hash Hash Function

Problem Explanation

Explanation:

To solve this problem, we can use dynamic programming. We can create a 2D array dp where dp[i][j] represents the length of the longest common suffix of subarrays nums1[0, i] and nums2[0, j] that end at nums1[i] and nums2[j] respectively. We iterate through both arrays and update the dp array accordingly. The maximum value in dp will give us the length of the longest common subarray. :

Solution Code

class Solution {
    public int findLength(int[] nums1, int[] nums2) {
        int m = nums1.length, n = nums2.length;
        int[][] dp = new int[m + 1][n + 1];
        int maxLen = 0;
        
        for (int i = 1; i <= m; i++) {
            for (int j = 1; j <= n; j++) {
                if (nums1[i - 1] == nums2[j - 1]) {
                    dp[i][j] = dp[i - 1][j - 1] + 1;
                    maxLen = Math.max(maxLen, dp[i][j]);
                }
            }
        }
        
        return maxLen;
    }
}

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