LeetCode 724: Find Pivot Index Solution

Problem Explanation

Explanation:

To solve this problem, we can iterate through the array and keep track of the total sum of all elements. Then, we can iterate again while updating the left sum and checking if the current index is a pivot index.

Calculate the total sum of all elements in the array.
Iterate through the array and at each index:
- Check if the left sum is equal to the total sum minus the current element and the left sum.
- If the condition is met, return the current index as the pivot index.
If no pivot index is found, return -1.

Time Complexity: O(n) where n is the number of elements in the array. Space Complexity: O(1)

Solution Code

class Solution {
    public int pivotIndex(int[] nums) {
        int totalSum = 0;
        for (int num : nums) {
            totalSum += num;
        }
        
        int leftSum = 0;
        for (int i = 0; i < nums.length; i++) {
            if (leftSum == totalSum - nums[i] - leftSum) {
                return i;
            }
            leftSum += nums[i];
        }
        
        return -1;
    }
}

Frequently Asked Questions

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