LeetCode 725: Split Linked List in Parts Solution
Master LeetCode problem 725 (Split Linked List in Parts), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
725. Split Linked List in Parts
Problem Explanation
Explanation
To split the linked list into k consecutive linked list parts, we first need to find the length of the linked list. Then, we calculate the size of each part as length of list / k. We distribute the remaining nodes (if any) to the first few parts. Finally, we iterate through the list to create the parts.
- Time Complexity: O(n) where n is the number of nodes in the linked list.
- Space Complexity: O(k) where k is the number of parts.
Solution Code
class Solution {
public ListNode[] splitListToParts(ListNode head, int k) {
ListNode[] parts = new ListNode[k];
int length = 0;
ListNode current = head;
while (current != null) {
length++;
current = current.next;
}
int partSize = length / k;
int extraNodes = length % k;
current = head;
for (int i = 0; i < k && current != null; i++) {
parts[i] = current;
int partLength = partSize + (extraNodes-- > 0 ? 1 : 0);
for (int j = 1; j < partLength; j++) {
current = current.next;
}
ListNode next = current.next;
current.next = null;
current = next;
}
return parts;
}
}Try It Yourself
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