LeetCode 755: Pour Water Solution

Master LeetCode problem 755 (Pour Water), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

755. Pour Water

Problem Explanation

Explanation:

The problem "Pour Water" can be solved by simulating the pouring process step by step. The idea is to pour water at a certain index and let it flow either left or right based on certain conditions. We repeat this process for each unit of water poured.

Algorithm:

  1. Start pouring water at the given index.
  2. Move the water to the left if possible until it reaches a lower level or the end of the array.
  3. If no lower level is found towards the left, move the water to the right until a lower level is found or the end of the array.
  4. If no lower level is found towards the right, pour the water at the original index.

Time Complexity: O(V * n) where V is the amount of water poured and n is the length of the heights array. Space Complexity: O(1)

: :

Solution Code

class Solution {
    public int[] pourWater(int[] heights, int V, int K) {
        for (int i = 0; i < V; i++) {
            int cur = K;
            while (cur > 0 && heights[cur] >= heights[cur - 1]) {
                cur--;
            }
            while (cur < heights.length - 1 && heights[cur] >= heights[cur + 1]) {
                cur++;
            }
            while (cur > K && heights[cur] >= heights[cur - 1]) {
                cur--;
            }
            heights[cur]++;
        }
        return heights;
    }
}

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