LeetCode 78: Subsets Solution
Master LeetCode problem 78 (Subsets), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
78. Subsets
Problem Explanation
Explanation
To generate all possible subsets of a given set, we can use a backtracking approach. We start with an empty subset and gradually add elements to it, considering each element in the input array. At each step, we either include the current element in the subset or skip it. This process generates all possible combinations of elements.
Algorithm:
- Initialize an empty list
resultto store all subsets. - Define a helper function
generateSubsetsthat takes parameters: the current index in the input array, the current subset being constructed, and the input arraynums. - In the helper function:
- Add the current subset to the
result. - Iterate over the elements in
numsstarting from the index provided:- Add the current element to the subset.
- Recursively call the helper function with the next index and the updated subset.
- Remove the last element from the subset to backtrack and explore other possibilities.
- Add the current subset to the
- Call the helper function with initial parameters: index = 0, current subset = empty list, and
nums. - Return the
resultcontaining all subsets.
Time Complexity:
The time complexity of this approach is O(2^N) where N is the number of elements in the input array. This is because for each element, there are two choices - either include it in the subset or skip it.
Space Complexity:
The space complexity is O(N * 2^N) to store all subsets, where N is the number of elements in the input array.
Solution Code
class Solution {
public List<List<Integer>> subsets(int[] nums) {
List<List<Integer>> result = new ArrayList<>();
generateSubsets(0, new ArrayList<>(), nums, result);
return result;
}
private void generateSubsets(int index, List<Integer> current, int[] nums, List<List<Integer>> result) {
result.add(new ArrayList<>(current));
for (int i = index; i < nums.length; i++) {
current.add(nums[i]);
generateSubsets(i + 1, current, nums, result);
current.remove(current.size() - 1);
}
}
}Try It Yourself
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