LeetCode 816: Ambiguous Coordinates Solution

Master LeetCode problem 816 (Ambiguous Coordinates), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

816. Ambiguous Coordinates

Medium

String Backtracking Enumeration

Problem Explanation

Explanation:

To solve this problem, we need to iterate through all possible ways of splitting the input string s into two parts such that each part can represent a valid coordinate. We then generate valid coordinate representations for each split and add them to the result list.

Iterate through all possible splits of the input string s.
For each split, generate all possible valid coordinate representations for the two parts.
Check for valid formats and add them to the result list.

Time Complexity: O(n^3) where n is the length of the input string s. Space Complexity: O(n) for storing the result list.

Solution Code

class Solution {
    public List<String> ambiguousCoordinates(String s) {
        List<String> result = new ArrayList<>();
        for (int i = 2; i < s.length() - 1; i++) {
            List<String> leftCoords = generateCoordinates(s.substring(1, i));
            List<String> rightCoords = generateCoordinates(s.substring(i, s.length() - 1));
            for (String left : leftCoords) {
                for (String right : rightCoords) {
                    result.add("(" + left + ", " + right + ")");
                }
            }
        }
        return result;
    }
    
    private List<String> generateCoordinates(String str) {
        List<String> coordinates = new ArrayList<>();
        if (str.length() == 1 || !str.startsWith("0")) {
            coordinates.add(str);
        }
        for (int i = 1; i < str.length(); i++) {
            String left = str.substring(0, i);
            String right = str.substring(i);
            if ((!left.startsWith("0") || left.equals("0")) && !right.endsWith("0")) {
                coordinates.add(left + "." + right);
            }
        }
        return coordinates;
    }
}

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