LeetCode 817: Linked List Components Solution
Master LeetCode problem 817 (Linked List Components), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
817. Linked List Components
Problem Explanation
Explanation
To solve this problem, we can iterate through the linked list and the given array nums at the same time. We can use a set to store the values in nums for faster lookup. While iterating through the linked list, we check if the current value and the next value are both in the set. If they are, we increment a counter for connected components. After iterating through the linked list, we return the total count of connected components.
- Time complexity: O(n) where n is the number of nodes in the linked list
- Space complexity: O(m) where m is the number of elements in the nums array
Solution Code
public int numComponents(ListNode head, int[] nums) {
Set<Integer> numSet = new HashSet<>();
for (int num : nums) {
numSet.add(num);
}
int count = 0;
while (head != null) {
if (numSet.contains(head.val) && (head.next == null || !numSet.contains(head.next.val))) {
count++;
}
head = head.next;
}
return count;
}Try It Yourself
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