LeetCode 83: Remove Duplicates from Sorted List Solution

Master LeetCode problem 83 (Remove Duplicates from Sorted List), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

83. Remove Duplicates from Sorted List

Easy

Linked List

Problem Explanation

Explanation

To solve this problem, we can iterate through the linked list and remove any duplicates we encounter. Since the list is sorted, duplicates will be adjacent to each other. We can traverse the list and compare each node with its next node. If they have the same value, we can skip the next node. If they have different values, we move to the next node.

Algorithm:

Initialize a pointer current to the head of the linked list.
Traverse the linked list while current and current.next are not null.
Compare the values of current and current.next.
If the values are the same, set current.next to current.next.next to remove the duplicate.
If the values are different, move current to current.next.
Return the modified linked list.

Solution Code

class Solution {
    public ListNode deleteDuplicates(ListNode head) {
        ListNode current = head;
        while (current != null && current.next != null) {
            if (current.val == current.next.val) {
                current.next = current.next.next;
            } else {
                current = current.next;
            }
        }
        return head;
    }
}

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