LeetCode 832: Flipping an Image Solution

Master LeetCode problem 832 (Flipping an Image), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

Problem Explanation

Explanation

To solve this problem, we need to first reverse each row of the input image matrix. Then, we invert the values in the matrix by flipping 0s to 1s and 1s to 0s. This process can be achieved by iterating through each row, reversing it, and then flipping the values.

Algorithm:

  1. Iterate through each row of the image matrix.
  2. Reverse each row.
  3. Invert the values in each row.

Time Complexity:

The time complexity of this algorithm is O(n^2), where n is the size of the input image matrix.

Space Complexity:

The space complexity is O(1) as we are modifying the input matrix in place.

Solution Code

class Solution {
    public int[][] flipAndInvertImage(int[][] image) {
        int n = image.length;
        
        for (int i = 0; i < n; i++) {
            int left = 0;
            int right = n - 1;
            while (left <= right) {
                int temp = image[i][left] ^ 1;
                image[i][left] = image[i][right] ^ 1;
                image[i][right] = temp;
                left++;
                right--;
            }
        }
        
        return image;
    }
}

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What is the time complexity of LeetCode 832 (Flipping an Image)?

The time complexity for LeetCode 832 (Flipping an Image) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

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