LeetCode 833: Find And Replace in String Solution
Master LeetCode problem 833 (Find And Replace in String), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
833. Find And Replace in String
Problem Explanation
Explanation:
To solve this problem, we will iterate through each replacement operation and update the string accordingly. We will check if the source string exists at the specified index in the original string. If it does, we will replace the source string with the target string.
Algorithm:
- Iterate through each replacement operation.
- For each operation, check if the source string exists at the specified index in the original string.
- If the source string exists, replace it with the target string.
- Return the final modified string after all replacement operations.
Time Complexity:
The time complexity of this approach is O(nmk), where n is the length of the input string, m is the maximum length of source or target strings, and k is the number of replacement operations.
Space Complexity:
The space complexity of this approach is O(n), where n is the length of the input string.
:
Solution Code
class Solution {
public String findReplaceString(String s, int[] indices, String[] sources, String[] targets) {
StringBuilder sb = new StringBuilder(s);
for (int i = 0; i < indices.length; i++) {
int index = indices[i];
String source = sources[i];
String target = targets[i];
if (s.substring(index, index + source.length()).equals(source)) {
sb.replace(index, index + source.length(), target);
}
}
return sb.toString();
}
}Try It Yourself
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