LeetCode 900: RLE Iterator Solution
Master LeetCode problem 900 (RLE Iterator), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation
To solve this problem, we can implement the RLEIterator class with two instance variables:
encoding: to store the input run-length encoded array.index: to keep track of the current position in the encoding array.
In the constructor, we initialize these variables. The next(n) method iterates through the encoded array based on the value of n. We exhaust the next n elements by decrementing the count at the current index and moving to the next index if the count becomes zero. We return the value at the current index after each iteration.
Solution Code
class RLEIterator {
int[] encoding;
int index;
public RLEIterator(int[] encoded) {
encoding = encoded;
index = 0;
}
public int next(int n) {
while (index < encoding.length) {
if (n > encoding[index]) {
n -= encoding[index];
index += 2;
} else {
encoding[index] -= n;
return encoding[index + 1];
}
}
return -1;
}
}Try It Yourself
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