LeetCode 972: Equal Rational Numbers Solution
Master LeetCode problem 972 (Equal Rational Numbers), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation:
To solve this problem, we can break down the rational numbers into their constituent parts - integer part, non-repeating part, and repeating part. We then convert these parts into their decimal equivalents and compare if they are equal. We can use a helper function to parse each part of the rational number and convert it to a decimal value. We need to handle repeating parts by multiplying the repeating part appropriately to account for the repeating pattern.
- Parse the integer part, non-repeating part, and repeating part from both strings.
- Convert each part into its decimal equivalent.
- Compare the decimal values to check if the rational numbers are equal.
- Handle repeating parts by multiplying appropriately.
Time Complexity:
The time complexity of this algorithm is O(N), where N represents the length of the input strings.
Space Complexity:
The space complexity is O(1) as we are not using any extra space proportional to the input size. :
Solution Code
class Solution {
public boolean isRationalEqual(String s, String t) {
double num1 = convertToDecimal(s);
double num2 = convertToDecimal(t);
return Math.abs(num1 - num2) < 1e-9;
}
private double convertToDecimal(String num) {
// Implement parsing and conversion logic here
}
}Try It Yourself
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What is the time complexity of LeetCode 972 (Equal Rational Numbers)?
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