LeetCode 976: Largest Perimeter Triangle Solution
Master LeetCode problem 976 (Largest Perimeter Triangle), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation
To find the largest perimeter of a triangle from the given array of side lengths, we can sort the array in descending order. Then, we iterate through the sorted array and check if the current three consecutive side lengths can form a valid triangle according to the triangle inequality theorem. If they can, we return the sum of those side lengths as the largest perimeter. If we reach the end of the array without finding a valid triangle, we return 0.
Algorithm:
- Sort the input array
numsin descending order. - Iterate through the sorted array starting from index 0.
- Check if nums[i] < nums[i+1] + nums[i+2]. If true, return the sum of the three side lengths.
- If no valid triangle is found, return 0.
Time Complexity: O(n log n) - Sorting the array takes O(n log n) time complexity. Space Complexity: O(1) - Only constant extra space is used.
Solution Code
class Solution {
public int largestPerimeter(int[] nums) {
Arrays.sort(nums);
for (int i = nums.length - 1; i >= 2; i--) {
if (nums[i] < nums[i - 1] + nums[i - 2]) {
return nums[i] + nums[i - 1] + nums[i - 2];
}
}
return 0;
}
}Try It Yourself
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