LeetCode 995: Minimum Number of K Consecutive Bit Flips Solution
Master LeetCode problem 995 (Minimum Number of K Consecutive Bit Flips), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
995. Minimum Number of K Consecutive Bit Flips
Problem Explanation
Explanation
To solve this problem, we can use a sliding window approach. We will iterate through the array nums from left to right. At each step, if the current element is 0 and we haven't flipped the current window starting at the current index, we will perform a flip. We will maintain a flipped array to keep track of whether a flip has been performed in the current window.
If we encounter a 0 and the current window has already been flipped, it means we need to perform another flip to make the current element 1. If it is not possible to perform a flip, we return -1.
The time complexity of this approach is O(n) where n is the length of the input array nums.
Solution Code
class Solution {
public int minKBitFlips(int[] nums, int k) {
int n = nums.length;
int[] flipped = new int[n];
int flips = 0;
int totalFlips = 0;
for (int i = 0; i < n; i++) {
if (i >= k) {
flips ^= flipped[i - k];
}
if ((nums[i] ^ flips) == 0) {
if (i + k > n) return -1;
flips ^= 1;
totalFlips++;
flipped[i] = 1;
}
}
return totalFlips;
}
}Try It Yourself
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