LeetCode 2220: Minimum Bit Flips to Convert Number Solution
Master LeetCode problem 2220 (Minimum Bit Flips to Convert Number), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2220. Minimum Bit Flips to Convert Number
Problem Explanation
Explanation
To solve this problem, we can iterate through the bits of the start and goal numbers from right to left. If the corresponding bits are different, we need to perform a bit flip operation. We can use a simple greedy approach where we flip the current bit if it differs between the two numbers, and then continue to the next bit.
The steps to convert start to goal will be equal to the number of bit flips required.
- Time Complexity: O(log(N)), where N is the maximum of
startandgoal. - Space Complexity: O(1).
Solution Code
class Solution {
public int minFlips(int start, int goal) {
int flips = 0;
for (int i = 0; i < 32; i++) {
if ((start & 1) != (goal & 1)) {
flips++;
}
start >>= 1;
goal >>= 1;
}
return flips;
}
}Try It Yourself
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