LeetCode 3133: Minimum Array End Solution

Master LeetCode problem 3133 (Minimum Array End), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3133. Minimum Array End

Problem Explanation

Explanation

To find the minimum possible value of the last element in the array, we need to construct an array of positive integers such that the result of the bitwise AND operation between all elements is x. We can achieve this by setting the last element to x and then filling the remaining elements with increasing values to satisfy the condition.

  1. Find the highest set bit position in x.
  2. Create a mask with all bits set to 1 up to the highest set bit position.
  3. Initialize the last element nums[n-1] as x.
  4. Fill the array backwards starting from nums[n-2] with values that maintain the bitwise AND operation to be x.
  5. Return the minimum possible value of nums[n-1].

Time complexity: O(log x)
Space complexity: O(1)

Solution Code

class Solution {
    public int findMinimumLastElement(int n, int x) {
        int highestSetBit = 31 - Integer.numberOfLeadingZeros(x);
        int mask = (1 << (highestSetBit + 1)) - 1;
        int[] nums = new int[n];
        nums[n - 1] = x;
        for (int i = n - 2; i >= 0; i--) {
            nums[i] = mask | (mask - 1);
        }
        return nums[n - 1];
    }
}

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